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Question 1 of 20
1. Question
1 pointsIf the value of log (0.317) = 0.3332 and log (0.318) = 0.3364 then find log (0.319)?
CorrectAnswer: 0.3396
Explanation:
log (0.317) = 0.3332
log (0.318) = 0.3364, then
log (0.319) = log (0.318) + (log (0.318) – log (0.317)) = 0.3396
IncorrectAnswer: 0.3396
Explanation:
log (0.317) = 0.3332
log (0.318) = 0.3364, then
log (0.319) = log (0.318) + (log (0.318) – log (0.317)) = 0.3396

Question 2 of 20
2. Question
1 pointsA box of 150 packets consists of 1 kg packets and 2 kg packets. Total weight of box is 264 kg. How many 2 kg packets are there?
CorrectAnswer: 114
Explanation
Let x = 2 kg Packs
y = 1 kg packs
x + y = 150
2x + y = 264
On solving,
x = 114 and y = 36
Therefore, Number of 2 kg Packs = 114.
IncorrectAnswer: 114
Explanation
Let x = 2 kg Packs
y = 1 kg packs
x + y = 150
2x + y = 264
On solving,
x = 114 and y = 36
Therefore, Number of 2 kg Packs = 114.

Question 3 of 20
3. Question
1 pointsFlight takes off at 2am from a place at 18N 1E and landed 10 hrs later at a place with coordinates 36N70W. What is the local time when the plane landed?
CorrectAnswer: 6: 40 AM
Explanation:
The destination place is 80 degree west to the starting place.
Hence the time difference between these two places is 5 hour 20 min. = (24hr*80/360).
When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours). Hence, the time at the destination place is 12 noon – 5:20 hours = 6: 40 AM
IncorrectAnswer: 6: 40 AM
Explanation:
The destination place is 80 degree west to the starting place.
Hence the time difference between these two places is 5 hour 20 min. = (24hr*80/360).
When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours). Hence, the time at the destination place is 12 noon – 5:20 hours = 6: 40 AM

Question 4 of 20
4. Question
1 pointsAn airplane moves from 9°N40°E to 9°N40°W. If the airplane starts at 10 am and takes 8 hours to reach the destination, find the local arrival time?
CorrectAnswer: 12:30 PM
Explanation: As it is moving from east to west longitude,
Add both i.e., 40+40=80
Then multiply by 4
80*4=320min
i.e., 5hrs 33min
So 8 – 5hr 30 min=2hr 30min
Hence the local arrival time is 10am + 2hr 30 min = 12:30 pm.
IncorrectAnswer: 12:30 PM
Explanation: As it is moving from east to west longitude,
Add both i.e., 40+40=80
Then multiply by 4
80*4=320min
i.e., 5hrs 33min
So 8 – 5hr 30 min=2hr 30min
Hence the local arrival time is 10am + 2hr 30 min = 12:30 pm.

Question 5 of 20
5. Question
1 pointsThe size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a program to receiver. There it waits for 10 milliseconds. And response will be back to programmer in 20 milliseconds. How much time the program takes to get a response back to the programmer, after it is sent?
CorrectAnswer: 30ms
Explanation: At receiver, it waits there for 10 ms and back to the programmer in 20 ms.
Then total time to get the response is 20 ms + 10 ms = 30 ms.
IncorrectAnswer: 30ms
Explanation: At receiver, it waits there for 10 ms and back to the programmer in 20 ms.
Then total time to get the response is 20 ms + 10 ms = 30 ms.

Question 6 of 20
6. Question
1 pointsA fisherman’s day is rated as good if he catches 9 fishes, fair if 7 fishes and bad if 5 fishes. He catches 53 fishes in a week and had all good, fair and bad days in the week. So how many good, fair and bad days did the fisher man had in the week?
CorrectAnswer: (4, 1, 2) and (3, 3, 1).
Explanation: X + y + z = 7 — (A)
9*x + 7*y + 5*z = 53 — (B)
multiply A by 9,
9*x + 9*y + 9*z = 35 — (C)
from B and C
2*y + 4*z = 10 — (D)
since all x, y and z are integers, there will be two possible values for y = 1 or 3
then z = 2 or 1 from (D)
for y = 1, z = 2
then x = 4
so 9*4 + 1*7 + 2*5 = 53…. Satisfied
now for y = 3, z = 1
then x = 3
so 9*3 + 3*7 + 1*5 = 53 …… Satisfied
so finally there are two solutions of this question
(x, y ,z) = (4, 1, 2) and (3, 3, 1).
IncorrectAnswer: (4, 1, 2) and (3, 3, 1).
Explanation: X + y + z = 7 — (A)
9*x + 7*y + 5*z = 53 — (B)
multiply A by 9,
9*x + 9*y + 9*z = 35 — (C)
from B and C
2*y + 4*z = 10 — (D)
since all x, y and z are integers, there will be two possible values for y = 1 or 3
then z = 2 or 1 from (D)
for y = 1, z = 2
then x = 4
so 9*4 + 1*7 + 2*5 = 53…. Satisfied
now for y = 3, z = 1
then x = 3
so 9*3 + 3*7 + 1*5 = 53 …… Satisfied
so finally there are two solutions of this question
(x, y ,z) = (4, 1, 2) and (3, 3, 1).

Question 7 of 20
7. Question
1 pointsPraveen catches 5 times more fishes than Surendra. If total number of fishes caught by Surendra and Praveen is 42, then number of fishes caught by Surendra?
CorrectAnswer: 6
Explanation: Let no. of fish Surendra catches = p
no. of fish caught by Praveen = r
r = 5p + p = 6p
r + p =42
then p = 6, r = 36
IncorrectAnswer: 6
Explanation: Let no. of fish Surendra catches = p
no. of fish caught by Praveen = r
r = 5p + p = 6p
r + p =42
then p = 6, r = 36

Question 8 of 20
8. Question
1 pointsThree companies are working independently and receiving the savings 20%, 30%, 40%. If these companies work combine, what will be their net savings?
CorrectAnswer: 30%
Explanation: Let total income is 100, so A =80, B=70, C=60
Total sum =210
Total money is 300, 300210=90
They are getting Rs.90, 90 is 30% of 300
So they are getting 30% savings
IncorrectAnswer: 30%
Explanation: Let total income is 100, so A =80, B=70, C=60
Total sum =210
Total money is 300, 300210=90
They are getting Rs.90, 90 is 30% of 300
So they are getting 30% savings

Question 9 of 20
9. Question
1 pointsThe ratio of incomes of Charan and David is 3:4.the ratio of their expenditures is 4:5. Find the ratio of their savings if the savings of Charan is one fourths of his income?
CorrectAnswer: 12/19
Explanation: Incomes = 3:4
Expenditures = 4:5
3x – 4y = 1/4(3x)
12x – 16y = 3x
9x = 16y
Y = 9x/16
Ratio of their savings = (3x – 4(9x/16)) / ((4x – 5(9x/16))) = 12/19
IncorrectAnswer: 12/19
Explanation: Incomes = 3:4
Expenditures = 4:5
3x – 4y = 1/4(3x)
12x – 16y = 3x
9x = 16y
Y = 9x/16
Ratio of their savings = (3x – 4(9x/16)) / ((4x – 5(9x/16))) = 12/19

Question 10 of 20
10. Question
1 pointsIf p (0) = 1, p (1) = 1 and p (N) = p (N1) – p (N2) then what is the value of p (6)?
CorrectAnswer: 1
Explanation: P (2) = p (1) – p (0) = 1 + 1 = 2
P (3) = 1
P (4) = 1
P (5) = 2
P (6) = 1
IncorrectAnswer: 1
Explanation: P (2) = p (1) – p (0) = 1 + 1 = 2
P (3) = 1
P (4) = 1
P (5) = 2
P (6) = 1

Question 11 of 20
11. Question
1 pointsIf A can copy 50 pages in 10 hours and A and B together can copy 70 pages in 10 hours, how much time does B takes to copy 26 pages?
CorrectAnswer: 3 hrs
Explanation: A can copy 50 pages in 10 hrs.
Capacity of A is 5 pages/hr.
Now A & B can copy 70 pages in 10hrs.
Capacity of A & B is 7 pages/hr.
Capacity of B = 2*7 – 5 = 9 pages/hr.
Therefore, to copy 26 pages B will need almost 3hrs.
IncorrectAnswer: 3 hrs
Explanation: A can copy 50 pages in 10 hrs.
Capacity of A is 5 pages/hr.
Now A & B can copy 70 pages in 10hrs.
Capacity of A & B is 7 pages/hr.
Capacity of B = 2*7 – 5 = 9 pages/hr.
Therefore, to copy 26 pages B will need almost 3hrs.

Question 12 of 20
12. Question
1 pointsA, B and C are 8 bit no’s. They are as follows:
A > 1 1 0 0 0 1 0 1
B > 0 0 1 1 0 0 1 1
C > 0 0 1 1 1 0 1 0
Find ((A – C) U B) =?
CorrectAnswer: 10111011
Explanation: To find AC, We will find 2′s compliment of C and them add it with A,
That will give us (AC)
2′s compliment of C = 1′s compliment of C + 1
= 11000101 + 1 = 11000110
A – C = 11000101 + 11000110
= 10001001
Now (AC) U B is .OR. logic operation on (AC) and B
10001001 .OR. 00110011
The answer is = 10111011, whose decimal equivalent is 187.
IncorrectAnswer: 10111011
Explanation: To find AC, We will find 2′s compliment of C and them add it with A,
That will give us (AC)
2′s compliment of C = 1′s compliment of C + 1
= 11000101 + 1 = 11000110
A – C = 11000101 + 11000110
= 10001001
Now (AC) U B is .OR. logic operation on (AC) and B
10001001 .OR. 00110011
The answer is = 10111011, whose decimal equivalent is 187.

Question 13 of 20
13. Question
1 pointsOne circular array is given (means memory allocation takes place in circular fashion) dimension (9×7) and starting address is 3000, What is the address of (2, 3)?
CorrectAnswer: 3012
Explanation: It’s a 9×7 Int array
So it requires 126 bytes for storing.
Because integer value need 2 bytes of memory allocation, and starting address is 3000
So starting address of 2×3 will be 3012.
IncorrectAnswer: 3012
Explanation: It’s a 9×7 Int array
So it requires 126 bytes for storing.
Because integer value need 2 bytes of memory allocation, and starting address is 3000
So starting address of 2×3 will be 3012.

Question 14 of 20
14. Question
1 pointsThe size of a program is N. And the memory occupied by the program is given by M = square root of 100N. If the size of the program is increased by 1% then how much memory now occupied?
CorrectAnswer: sqrt(101 * N)
Explanation:
M = sqrt (100N)
N is increased by 1%
Therefore new value of N = N + (N/100)
= 101N/100
M = sqrt (100 * (101N/100) )
Hence, we get M = sqrt(101 * N)
IncorrectAnswer: sqrt(101 * N)
Explanation:
M = sqrt (100N)
N is increased by 1%
Therefore new value of N = N + (N/100)
= 101N/100
M = sqrt (100 * (101N/100) )
Hence, we get M = sqrt(101 * N)

Question 15 of 20
15. Question
1 pointsA Volvo bus started from bus stand at 8.00 am and after 30 min staying at destination, it returned back to the bus stand. The destination is 27 miles from the bus stand at 18 miles per hour. The speed of the Volvo bus in return is 50 percent fast than previous speed. At what time it returns to the bus stand?
CorrectAnswer: 11 a.m.
Explanation: A Volvo bus cover 27 mile with 18 mph
time taken = 27/18 = 1 hour 30 min.
and it wait at stand = 30 min.
after this, speed of return increase by 50%
so 50% of 18 mph = 9mph
Total speed of returning = 18 + 9 = 27mph.
Then in return it take 27/27 = 1 hour
then total time in journey = 1 + 1:30 + 00:30 = 3 hours.
so it will come at 8 + 3 = 11 a.m.
IncorrectAnswer: 11 a.m.
Explanation: A Volvo bus cover 27 mile with 18 mph
time taken = 27/18 = 1 hour 30 min.
and it wait at stand = 30 min.
after this, speed of return increase by 50%
so 50% of 18 mph = 9mph
Total speed of returning = 18 + 9 = 27mph.
Then in return it take 27/27 = 1 hour
then total time in journey = 1 + 1:30 + 00:30 = 3 hours.
so it will come at 8 + 3 = 11 a.m.

Question 16 of 20
16. Question
1 pointsIn two dimensional array X(7,9) each element occupies 2 bytes of memory .If the address of first element X(1,1)is 1258 then what will be the address of the element X(5,8)?
CorrectAnswer: 1338
Explanation: The address of first element x[1][1] is 1258
and also 2 byte of memory is given.
Now, the address of element x[5][8] = 1258 + 5*8*2 = 1258 + 80 = 1338
So the answer is 1338.
IncorrectAnswer: 1338
Explanation: The address of first element x[1][1] is 1258
and also 2 byte of memory is given.
Now, the address of element x[5][8] = 1258 + 5*8*2 = 1258 + 80 = 1338
So the answer is 1338.

Question 17 of 20
17. Question
1 pointsIn Yerraguntla, temperature at noon varies according to –t ^{2/2} + 8 t + 3, where t is elapsed time. Find how much temperature more or less in 4 p m to 9 p m.
CorrectAnswer: At 9 pm, 7.5 more
Explanation: In given equation, put t = 9,
Result = 34.5
Now, put t = 4, result = 27
Required value = 34.527= 7.5
IncorrectAnswer: At 9 pm, 7.5 more
Explanation: In given equation, put t = 9,
Result = 34.5
Now, put t = 4, result = 27
Required value = 34.527= 7.5

Question 18 of 20
18. Question
1 pointsA person had to multiply two numbers. Instead of multiplying by 35, he multiplied by 53 and the product went up by 540. What was the raised product?
CorrectAnswer: 1590
Explanation: Let one number be x
Now, (X×53) – (x×35) = 540
X = 30
Therefore product = 53×30 = 1590
IncorrectAnswer: 1590
Explanation: Let one number be x
Now, (X×53) – (x×35) = 540
X = 30
Therefore product = 53×30 = 1590

Question 19 of 20
19. Question
1 pointsThe total expense of a boarding house is partly fixed and partly variable with the number of boarders. The charge is Rs.70 per head when there are 25 boarders and Rs.60 when there are 50 boarders. Find the charge per head when there are 100 boarders.
CorrectAnswer: 55
Explanation: Let a = fixed cost and k = variable cost and n = number of boarders
When 25 boarder cost = 25*70 = 1750
i.e. 1750 = a + 25k
When 50 boarder cost = 50*60 = 3000
i.e. 3000 = a + 50k
On solving, 3000 – 1750 = 25k
i.e. 1250 = 25k
i.e. k = 50
Therefore, a = 500
So total cost when 100 boarders
c = a + 100k = 500 + 100*50 = 5500
Hence cost per head = 5500/100 = 55
IncorrectAnswer: 55
Explanation: Let a = fixed cost and k = variable cost and n = number of boarders
When 25 boarder cost = 25*70 = 1750
i.e. 1750 = a + 25k
When 50 boarder cost = 50*60 = 3000
i.e. 3000 = a + 50k
On solving, 3000 – 1750 = 25k
i.e. 1250 = 25k
i.e. k = 50
Therefore, a = 500
So total cost when 100 boarders
c = a + 100k = 500 + 100*50 = 5500
Hence cost per head = 5500/100 = 55

Question 20 of 20
20. Question
1 pointsAchyut bought 5 pens, 7 pencils and 4 erasers. Rajesh bought 6 pens, 8 erasers and 14 pencils for an amount which was half more than what Achyut had paid. What % of the total amount paid by Achyut was paid for pens?
CorrectAnswer: 62.5%.
Explanation: Let, 5 pens + 7 pencils + 4 erasers = x rupees
So 10 pens + 14 pencils + 8 erasers = 2*x rupees
Also mentioned, 6 pens + 14 pencils + 8 erasers = 1.5*x rupees
So (106) = 4 pens = (2 – 1.5)x rupees
So 4 pens = 0.5x rupees => 8 pens = x rupees
So 5 pens = 5x/8 rupees = 5/8 of total
(Note x rupees is total amount paid by Achyut)
i.e. 5/8 = 500/8% = 62.5%.
IncorrectAnswer: 62.5%.
Explanation: Let, 5 pens + 7 pencils + 4 erasers = x rupees
So 10 pens + 14 pencils + 8 erasers = 2*x rupees
Also mentioned, 6 pens + 14 pencils + 8 erasers = 1.5*x rupees
So (106) = 4 pens = (2 – 1.5)x rupees
So 4 pens = 0.5x rupees => 8 pens = x rupees
So 5 pens = 5x/8 rupees = 5/8 of total
(Note x rupees is total amount paid by Achyut)
i.e. 5/8 = 500/8% = 62.5%.